0.5x^2-10x-1200=0

Solution for 0.5x^2-10x-1200=0 equation:

0.5x^2-10x-1200=0

a = 0.5; b = -10; c = -1200;
Δ = b2-4ac
Δ = -102-4·0.5·(-1200)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-50}{2*0.5}=\frac{-40}{1}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+50}{2*0.5}=\frac{60}{1}
=60
$